4 Triangles In A Square
I give thanks Jumar for the suggestion!
A square has a side length of l cm. Four right triangles with legs of 40 cm and thirty cm are placed along the four corners of the foursquare, every bit shown below.
What is the area of the region inside the foursquare not covered by the four triangles? In other words, what is the area of the region shaded in light-green?
As usual, watch the video for a solution.
Four Triangles In A Square Puzzle
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"All will be well if you use your heed for your decisions, and mind just your decisions." Since 2007, I have devoted my life to sharing the joy of game theory and mathematics. MindYourDecisions at present has over 1,000 free articles with no ads cheers to community support! Help out and become early on access to posts with a pledge on Patreon.
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Answer To Iv Triangles In A Foursquare Puzzle
(Pretty much all posts are transcribed quickly after I make the videos for them–please let me know if there are any typos/errors and I will right them, thanks).
Consider 2 adjacent right triangles. Since each has legs of 30 and 40, each has a hypotenuse equal to 50 (each is a 3-4-5 right triangle scaled by 10). The two triangles overlap to form another triangle shown in imperial.
Because the two triangles are rotated 90 degrees, their hypotenuses meet at a right angle. And then the two angles in the purple triangle are one of each of the acute angles of the blueish triangle. Thus the purple triangle is similar to the bluish triangle.
Now we will solve for the hypotenuse of the royal triangle. The small leg of the blue triangle is thirty, and then the distance from angle A to the right corner of the square is fifty – 30 = 20. And then the longer leg of the blueish triangle is 40, so the altitude from bending B to the left corner of the foursquare is 10. This means the hypotenuse of the majestic triangle is 50 – x – 20 = 20.
The blue triangle has an expanse equal to 30×40/2 = 600. The royal triangle is similar to the blue triangle, and their hypotenuses are in a ratio of 20/fifty = two/v. Thus the regal triangle'due south surface area to the blue triangle's is the squared ratio (2/5)2, and then its area is 600(2/five)2 = 96.
We can so observe the dark-green region'south area past adding and subtracting the areas of relevant shapes.
The green region's surface area is equal to the entire square's expanse minus 4 times a blue triangle'south surface area plus 4 times the purple triangle's expanse (nosotros demand to add dorsum the overlapping regions). Thus we accept:
dark-green area
= square's area – 4(bluish triangle) + 4(majestic triangle)
= fifty2 – 4(600) + 4(96)
= 2500 – 2400 + 384
= 484
Thus the light-green region has an surface area equal to 484.
4 Triangles In A Square,
Source: https://mindyourdecisions.com/blog/2021/10/11/four-triangles-in-a-square-puzzle/
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